Sound Distance Attenuation Calculator

Enter the sound level at a reference distance and a new distance. The calculator gives the level there, for a point source in a free field, where each doubling of distance lowers the level by about 6.02 dB.

dB
m
m
Enter both distances in the same unit. Feet or any other unit gives the same result, because only the ratio of the distances matters.
Decimal places in the result (rounded half up)
Sound level at the new distance —dB
Change—
Distance ratio (new distance ÷ reference distance)—
The value copied is the sound level as a number, without commas. To enter a negative level, type "-" before the number.

The assumptions: a point source in a free field

This calculator is limited to these conditions:

It does not account for the behavior of a line source (a line array), reflections from walls or floors, reverberation, absorption of sound by the air, wind or the effect of the ground. In a real room or outdoors, these make the level different from the result here.

How it is calculated

For a point source in a free field, the sound level falls as the distance grows (the inverse square law).

Doubling the distance lowers the level by about 6.02 dB. Ten times the distance lowers it by 20 dB. Halving the distance raises it by about 6.02 dB.

Distance ratio and change

Distance ratio (new ÷ reference) Change
0.5 × (half) +6.02 dB
2 × −6.02 dB
3 × −9.54 dB
4 × −12.04 dB
5 × −13.98 dB
10 × −20.00 dB
100 × −40.00 dB

Examples

Things to know

Frequently asked questions

How many dB does the level fall when the distance doubles?

For a point source in a free field, about 6.02 dB.

Does this hold indoors too?

No. A room has reflections from the walls, floor and ceiling and has reverberation, so the level can fall off by less than this formula says. This calculator is for a free field without reflections.

Can I use it for a line array speaker?

A line array (line source) spreads sound differently from a point source. Over some range the level falls off by less than for a point source when the distance doubles, so it is not covered here.

Does the reference distance have to be 1 m?

No. Only the ratio of the distances matters, so going from 2 m to 8 m or from 1 m to 4 m gives the same change (−12.04 dB).